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3x^2-6x-2.75=0
a = 3; b = -6; c = -2.75;
Δ = b2-4ac
Δ = -62-4·3·(-2.75)
Δ = 69
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{69}}{2*3}=\frac{6-\sqrt{69}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{69}}{2*3}=\frac{6+\sqrt{69}}{6} $
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